/*
Problem Description
we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).
Input
On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.
Output
for each case, you should the result of y+f(x) on a line.
Sample Input
6
R 1
P 2
G 3
r 1
p 2
g 3
Sample Output
19
18
10
-17
-14
-4
 */
package com.yuan.algorithms.practice201511;

import java.util.Scanner;

/**
 * @author YouYuan
 * <br>E-mail:1265161633@qq.com
 * <br>创建时间：2015年11月21日 上午9:10:12
 * <br>说明:
 */
public class 字母函数相加 {

	static Scanner in = new Scanner(System.in);
	public static void main(String[] args) {
		while(in.hasNext()) {
			int t = in.nextInt();
			while(t-- > 0) {
				char x = in.next().charAt(0);
				int y = in.nextInt();
				int temp = 0;
				if (x >= 'a' && x <= 'z') {
					temp = -(x - 96);
				} else {
					temp = x - 64;
				}
				System.out.println((y+temp));
			}
		}
	}

}
